# Line slope calculator 2x+8y=64

**Straight line given by points A[0; 8] and B[8; 6]**

## Calculation:

**Slope-intercept form of line:**y = -0.25x+8

**Canonical form of the line equation:**2x+8y-64 = 0

**Parametric form of the line equation:**

x = 8t

y = -2t+8 ; t ∈ R

**Slope:**m = -0.25

**Slope angle of line: φ =**-14°2'10″ = -0.245 rad

**X intercept:**x

_{0}= 32

**Y intercept:**y

_{0}= q = 8

**Distance line from the origin:**d

_{0}= 7.7611

**The length of the segment AB: |AB| =**8.2462

**Vector: AB =**(8; -2)

**Normal vector: n =**(2; 8)

**Midpoint of the segment AB: M =**[4; 7]

**Perpendicular Bisector equation:**8x-2y-18 = 0

**Vector OA = (0; 8) ; |OA| = 8**

**Vector OB = (8; 6) ; |OB| = 10**

**Scalar product OA .OB = 48**

**Angle ∠ AOB = 53°7'48″ = 0.9273 rad**